[tex]log_a(b)=c[/tex] translates to [tex]a^c=b[/tex] and [tex]log_a(b^c)=clog_a(b)[/tex] so
4096=16^3 [tex]log_{3x-2}(4096)=3[/tex] [tex]log_{3x-2}(16^3)=3[/tex] [tex]3log_{3x-2}(16)=3[/tex] divide both sides by 3 [tex]log_{3x-2}(16)=1[/tex] translate [tex](3x-2)^1=16[/tex] 3x-2=16 add 2 to both sides 3x=18 divide both sides by 3 x=6
