Respuesta :

WojtekR
From double-angle formula we know that:

[tex]\sin(2\theta)=2\sin\theta\cos\theta[/tex]

so (for θ = c/2):

[tex]\sin c=\sin(2\cdot\frac{c}{2})=2\sin(\frac{c}{2})\cos(\frac{c}{2})[/tex]

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