Given the equation of the circle (x - 9) 2 + y 2 = 484, the center of the circle is located at __________, and its radius has a length of __________ units.
The eq (x-9)^2+y^2=484 is of the form (x-h)^2+(y-k)^2=r^2 Where (h,k) are the coordinates of the centre ofa circle And r is the radius of the circle. Now , in this question , h=9 and k=0 so coordinates of the centre are (9,0) And radius is root of 484which is 22
