Answer:
Solution:- (D)
−
100
J
As the work is done by the system and heat is added to the system, thus the work done will be negative and the value of
q
will be positive.
Therefore,
W
=
−
140
J
q
=
40
J
As we know that,
Δ
E
=
q
+
W
∴
Δ
E
=
40
+
(
−
140
)
=
−
100
J
Hence the change in internal energy will be
−
100
J
.
Explanation:
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