Respuesta :

mreijepatmat
x²+7x-30
Find the roots of this trinomial:
x' = [-b+√(b²-4ac)]/2a]      and      x" = [-b-√(b²-4ac)]/2a]

x' = [-7+√(7²-4(1)(-30)]/2   and      x" = [-7-√(7²-4(1)(-30)]/2

x' = 3     and x" = -10
a(x-x')(x-x")

(x-3)(x+10) [Answer A]

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