Answer:
[tex]\texttt{Volume of pyramid }=\frac{x^2y}{3}[/tex]
Step-by-step explanation:
[tex]\texttt{Volume of pyramid }=\frac{1}{3}\times \texttt{Base Area}\times \texttt{Height}[/tex]
Base area of pyramid = Area of square base with side x = x²
Height of pyramid = y
[tex]\texttt{Volume of pyramid }=\frac{1}{3}\times x^2\times y=\frac{x^2y}{3}[/tex]
