destinydasilva25 destinydasilva25
  • 23-02-2018
  • Mathematics
contestada

The area of a rectangle is 56 cm. The length is 2 cm more than x and the width is 5 cm less than twice x. solve for x. Round to the nearest whole number.

Respuesta :

jcherry99
jcherry99 jcherry99
  • 25-02-2018
Area = L * W
Area = (x + 2)(2x - 5) = 56
x^2 +4x - 5x - 10 = 56
x^2 - x - 10 = 56
x^2 - x - 66 This does not factor nicely

You have to use the quadratic formula.
a = 1
b = - 1
c = - 66

x = (-b) +/- sqrt(b^2 - 4ac)
      ================
                        2a

x = 1 + /- sqrt(1^2 - 4(1)(-66)
      ===================
                        2(1)

 = 1 +/- sqrt (265)
    ==============
            2

= 17.279/2

= 8.639 which rounds to 9
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