[tex]\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}\\\\
A=Pe^{rt}\qquad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$7000\\
r=rate\to 5.05\%\to \frac{5.05}{100}\to &0.0505\\
t=years\to &5
\end{cases}
\\\\\\
A=7000e^{0.0505\cdot 5}\implies A=7000e^{0.2525}[/tex]
