chelseapelcher chelseapelcher
  • 26-02-2018
  • Mathematics
contestada

-a+18ab-2b^2+14a^-12ab-b^

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zrh2sfo zrh2sfo
  • 26-02-2018
Simplify the following:
14/(a^12) - 2 b^2

Put each term in 14/(a^12) - 2 b^2 over the common denominator a^12: 14/(a^12) - 2 b^2 = 14/a^12 - (2 a^12 b^2)/a^12:
14/a^12 - (2 a^12 b^2)/a^12

14/a^12 - (2 a^12 b^2)/a^12 = (14 - 2 a^12 b^2)/a^12:
(14 - 2 a^12 b^2)/a^12

Factor 2 out of 14 - 2 a^12 b^2:
Answer:  (2 (7 - a^12 b^2))/a^12
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