remove 3 outside of the parentheses by dividing both sides
[tex] \frac{3}{3} (7 + 5)(3x - 2) = \frac{0}{3}[/tex]
⬇
[tex](7x + 5)(3x - 2) = 0 [/tex]
一一一一一
Now there is two equations that are equal to zero
[tex]7x + 5 = 0 [/tex]
⬇
[tex] -\frac{5}{7} [/tex]
～～～
[tex]3x - 2 = 0 [/tex]
[tex]x = \frac{2}{3} [/tex]
一一一一一
x1=
[tex] - \frac{5}{7} [/tex]
x2=
[tex] \frac{2}{3} [/tex]
