Answer:
See attached file
Step-by-step explanation:
The given inequality is [tex]3x+8\ge11[/tex]
We subtract 8 from both sides to get:
[tex]3x+8-8\ge11-8\\3x+0\ge11-8\\3x\ge3[/tex]
Divide both sides by 3
[tex]\frac{3x}{3} \ge \frac{3}{3}[/tex]
[tex]x \ge 1[/tex]
To represent this on the number line, we draw a closed circle at 1 on the number line and direct the arrow to the right.
